Mnemolth Posted September 13, 2002 Share Posted September 13, 2002 This is a simple idea but hopefully a powerful one. There's a lot of sh*t in the world. And many of you would no doubt have had your fair share of jaded cynicism, justified or otherwise. This thread is intended as an opportunity to show just a small candle flame of the enormous shining light that can be humanity. If you have any questions from your homework or assignments, post them here, and hopefully someone will get back to you with an answer. Free advice with no strings attached. Unconditional generosity. From strangers and friends alike. An antidote to the ugliness of the world. Of course, it goes without saying that the success of this thread depends on the participation of the members of the forum. Here are a few basic guidelines ( and they are just guidelines, nothing more): 1. Ask simple questions that can be answered. Or at least start with those. If your questions are too involved and require hours of work from others, that may be asking too much. You gotta do some stuff yourself. ;) 2. If you have some knowledge to impart and you have a bit of time to kill why not help those who are asking for help. Sure it may take you 10 or 20 minutes, but hey, you'd be helping someone out. Life is too short to waste on doing nothing constructive. 3. If you do get help, be understanding and grateful. People give their advice free of charge, so appreciate the effort they have put in and express that appreciation. If the advice is inaccurate or plain wrong, cast no blame. The advice is given as is. Its the thought that counts. Remember, being good is actually 'cool'. :) Link to comment Share on other sites More sharing options...
Char! Posted September 17, 2002 Share Posted September 17, 2002 [color=teal][size=1]Whoa... Righteous... Unfortunately, no one's biting... I don't really need any advice at this precise moment in time, but I just don't wanna see such an awesome thread like this go to waste. C'mon people, you know you've got problems... :) --Mike[/color][/size] Link to comment Share on other sites More sharing options...
Genkai Posted September 17, 2002 Share Posted September 17, 2002 i read this and promised id reply after dinner, but... no, i didn't... it's a good idea, but if we have a question about homework, it'll take a while to get answered, and life's problems normally get answered through their own threads.... i dunno... Link to comment Share on other sites More sharing options...
Char! Posted September 17, 2002 Share Posted September 17, 2002 [color=teal][size=1]Well, it doesn't really have to be limited to homework. It could be about anything, really, kind of like those newspaper columns where "Confused In Pittsburgh" or whatever asks stuff for an uninterested third party to answer. Though, I guess we'd be interested... right? RIGHT?!? Gah, I need to stop being so hyper... whee... --Mike[/color][/size] Link to comment Share on other sites More sharing options...
Mnemolth Posted September 18, 2002 Author Share Posted September 18, 2002 Well....actually I was hoping for something more concrete, more substantial than just 'advice'. Like maybe you have a problem with basic Calculus, you're just a little unclear about differentiation and integration. Someone here may want to take the time to explain it to you. Give you a basic formula like: d(Ax^b)/dx = (b)Ax^(b-1) where A and b are numbers. And explain it clearly to you how it works. Some of you may be doing computer science and are a little unclear about 'Recursion', and can ask, and some can answer back and explain that it is a routine/procedure that calls itself, adding that there needs to be a 'base' case which MUST be true at some time so that the loop will stop. Others of you may be doing law, and have some trouble understanding a particular case (like the earlier one this year about drug testing in schools). You can ask someone to download it and read it and answer your queries. You can ask questions about vague stuff, like there is a thread here on Etiquette, and that's easy to answer, its just opinion, and its fun to express what you think and let other people know. But that's not what I'm after. That doesn't require actual work, research and some serious thinking. As I said before, this is more about giving than about receiving. And the things you give have to be of value, so that people can look upon the world and know that there is good in it, in a tangible and obvious way, directly related to them and not as some abstract thought, not just as a warm and fuzzy feeling but something that can directly help them, something that makes them think, wow, someone actually spent 1/2 hr of their time doing MY homework, and for FREE, with NO strings attached!! I'm pleasantly shocked. Its gone a a little way to making me believe in people again. And wouldn't that be nice? As for timely responses, well you should be able to get a reply within 24 hrs. It just depends on the question and if anyone knows the answer or can show it to you. There's no harm in trying. You're getting it for free anyways. I know some of you out there may be rolling their eyes, saying this will never work. No one is gonna be wasting their time helping strangers. The people who wanna help probably don't have the knowledge and the people who have the knowledge probably don't wanna help. Well, I think this thread is gonna bust too. But why don't you come along and prove me wrong? ;) PS: I guess some people can 'register' by posting their areas of 'expertise' (I use that term VERY VERY lightly). Just to give an idea. Me, personally, I know a little about world politics and news, law, some maths including discrete maths and calculus, and a little computer stuff. Link to comment Share on other sites More sharing options...
Mitch Posted September 18, 2002 Share Posted September 18, 2002 [color=red]Mnemolth, this is wonderful idea. To bad no one's biting as Char! said earlier. Well, I'll list my areas of expertise to I suppose. I'm really good at writing, and ok at English. I know many works of literature and so on. I'm also ok at science, I mostly like Biology, but I know a few other forms of science than that. That's about all...I mean I'm only 15, so yeh...[/color] Link to comment Share on other sites More sharing options...
Senor Ding Dong Posted September 18, 2002 Share Posted September 18, 2002 i need help.....sorta...... in my seventh grade math class, we took a test yesterday, and not everyone finished (me being one). see, on the first problem, we have a huge triangle, and a little triangle. we have to find the # of little triagles that can fit inside the bigger triangle, and then fit them inside there. please help me, and be a good samaritan........ Link to comment Share on other sites More sharing options...
Char! Posted September 18, 2002 Share Posted September 18, 2002 [color=teal][size=1][b]Well, I wouldn't really suggest you look to me for help in academics, but I'm a high school sophomore, so anything up to there I could probably help someone with. --Mike[/b][/size][/color] Link to comment Share on other sites More sharing options...
Senor Ding Dong Posted September 18, 2002 Share Posted September 18, 2002 ok, i just need to know ...how you findout how many small triangles can fit inside the bigger triangle? btw...skill factor and might be key words there...i dunno.... Link to comment Share on other sites More sharing options...
Char! Posted September 18, 2002 Share Posted September 18, 2002 [QUOTE][i]Originally posted by clowmet [/i] [B]ok, i just need to know ...how you findout how many small triangles can fit inside the bigger triangle? btw...skill factor and might be key words there...i dunno.... [/B][/QUOTE] [color=teal][size=1][b]Well, I don't really know about any helpful equations or whatever... Tell me, are you given the lengths of the sides of the two triangles, or are they just there?[/b][/size][/color] Link to comment Share on other sites More sharing options...
Senor Ding Dong Posted September 18, 2002 Share Posted September 18, 2002 one of the sides of the triangles are given, i believe....but the teacher givesus rulers for the other sides. Link to comment Share on other sites More sharing options...
Mitch Posted September 18, 2002 Share Posted September 18, 2002 [color=red]Then you just times the length of the first side of the triangle by 3 since the sides on a triangle are all equal...I think, but don't take my word for it because I suck at math. [/color] Link to comment Share on other sites More sharing options...
Mnemolth Posted September 19, 2002 Author Share Posted September 19, 2002 Hi there clowmet, glad to see someone giving this a chance. ;) Your question was rather vague, but I'll give it a try. Ok, I don't know how much you know, so I'm just gonna assume you know as little as possible ok? Please don't be offended. Its easier for me to explain everything in one go this way. To find the number of smaller triangles that can fit into a bigger one you need to find the AREA of BOTH triangles and DIVIDE the AREA of the big triangle by the area of the small triangle. I'll explain. 1. First step is to find the area of the triangle. How to do that? Well that depends on what kind of triangle it is. This is where I would have liked you to have more details in your question. As it is I don't know what TYPE of trinagles were are talking about, and whether the smaller triangle is the same TYPE as the bigger triangle, or whether they are both of different types. [IMG]http://falkor.anu.edu.au/~ely/triangles.gif[/IMG] Sorry about the sucky format, I dunno how to draw diagrams on posts (if that's possible at all). Anyways, the sides of a Triangle are A ro B, B to C and C to A In the above figures a) is an [b]equilateral[/b] triangle, that is ALL its sides are equal. AB=BC=AC In the above figures b) is an [b]isoceles[/b] triangle, that is TWO of its sides are equal. AB=AC In the above figures c) is a [b]right-angle[/b] triangle, that is TWO of its joint at a right-angle (90 degrees angle). This kind of triangle can also be an [b]isoceles[/b] triangle. In the above figures d) NONE of the sides are equal and there is NO right-angle. The basic formula for calculating the AREA of a TRIANGLE is: 1/2 b x h, where b is the 'base side' and h ='height' Working with the above diagrams, a) and b), BC = 'base side' and AD is the 'height' So Area of Triangle for a) and b) are: 1/2 x BC x AD For c) all you need to do is: 1/2 x BC x AC. IMPORTANT: It is the sides of the two ADJACENT(means next to each other) sides to the RIGHT-ANGLE that is multiplied. In this case it would be 1/2 x 5 x 10 = 25 For d) its a little more complicated. You need to find the SUM of TWO triangles. Triangle ABD and Triangle BCD. So area is (1/2 x BD x AD) + (1/2 x BD x DC) 2. Once you have the area of the BOTH triangles, let's say X is Area of smaller triangle and Y is area of big one, then Number of small triangles that fit into bigger one is: Y / X, or to put it another way Y divided X This should give you a number and maybe some fractions. ROUND downwards for your answer! Sounds complicated? It isn't, its just explaining it via the Internet that makes it seem complicated. In person I can probably explain to you in less than 5 mins! ;) Cheers Link to comment Share on other sites More sharing options...
Mitch Posted September 19, 2002 Share Posted September 19, 2002 [QUOTE][i]Originally posted by Mnemolth [/i] [B]Hi there clowmet, glad to see someone giving this a chance. ;) Your question was rather vague, but I'll give it a try. Ok, I don't know how much you know, so I'm just gonna assume you know as little as possible ok? Please don't be offended. Its easier for me to explain everything in one go this way. To find the number of smaller triangles that can fit into a bigger one you need to find the AREA of BOTH triangles and DIVIDE the AREA of the big triangle by the area of the small triangle. I'll explain. 1. First step is to find the area of the triangle. How to do that? Well that depends on what kind of triangle it is. This is where I would have liked you to have more details in your question. As it is I don't know what TYPE of trinagles were are talking about, and whether the smaller triangle is the same TYPE as the bigger triangle, or whether they are both of different types. [IMG]http://falkor.anu.edu.au/~ely/triangles.gif[/IMG] Sorry about the sucky format, I dunno how to draw diagrams on posts (if that's possible at all). Anyways, the sides of a Triangle are A ro B, B to C and C to A In the above figures a) is an [b]equilateral[/b] triangle, that is ALL its sides are equal. AB=BC=AC In the above figures b) is an [b]isoceles[/b] triangle, that is TWO of its sides are equal. AB=AC In the above figures c) is a [b]right-angle[/b] triangle, that is TWO of its joint at a right-angle (90 degrees angle). This kind of triangle can also be an [b]isoceles[/b] triangle. In the above figures d) NONE of the sides are equal and there is NO right-angle. The basic formula for calculating the AREA of a TRIANGLE is: 1/2 b x h, where b is the 'base side' and h ='height' Working with the above diagrams, a) and b), BC = 'base side' and AD is the 'height' So Area of Triangle for a) and b) are: 1/2 x BC x AD For c) all you need to do is: 1/2 x BC x AC. IMPORTANT: It is the sides of the two ADJACENT(means next to each other) sides to the RIGHT-ANGLE that is multiplied. In this case it would be 1/2 x 5 x 10 = 25 For d) its a little more complicated. You need to find the SUM of TWO triangles. Triangle ABD and Triangle BCD. So area is (1/2 x BD x AD) + (1/2 x BD x DC) 2. Once you have the area of the BOTH triangles, let's say X is Area of smaller triangle and Y is area of big one, then Number of small triangles that fit into bigger one is: Y / X, or to put it another way Y divided X This should give you a number and maybe some fractions. ROUND downwards for your answer! Sounds complicated? It isn't, its just explaining it via the Internet that makes it seem complicated. In person I can probably explain to you in less than 5 mins! ;) Cheers [/B][/QUOTE] [color=red] I knew you would now, Mnemolth, I was kinda right, right? Heh, well, I tried to help, but I suck at math. Well, at least he answered the question...:cross: This really is a good idea....[/color] Link to comment Share on other sites More sharing options...
User Name Posted September 19, 2002 Share Posted September 19, 2002 [SIZE=4]Jeeze, you really do LOVE to show off, don't you? Righty then, history question - What were the major factors contributing to WW2 ? [/SIZE] Link to comment Share on other sites More sharing options...
Guest gojay Posted September 19, 2002 Share Posted September 19, 2002 :babble: [size=1][color=blue]Here's my homework problem, *note that I'm a High school junior* the subject's Algebra II ::nervous:[/size][/color] If x+y=7 and z=3x+8, what is the value of z? [size=1][color=blue]I only need help with this one problem.[/size][/color]:cool: Link to comment Share on other sites More sharing options...
Corey Posted September 19, 2002 Share Posted September 19, 2002 [QUOTE][i]Originally posted by gojay [/i] [B] If x+y=7 and z=3x+8, what is the value of z? [/B][/QUOTE] Ouch... Geometry1 here... Ummm... I think it might possibly be... Does it give you any other info at all? And if not, what method are you supposed to use to solve it (i.e. Pythagorean Theorem, etc.)... Link to comment Share on other sites More sharing options...
Genkai Posted September 19, 2002 Share Posted September 19, 2002 er, here's a problem, though it may sound stupid.. are there any teas that'll help with breating problems or a respiratory infection, or when asthma is giving you trouble?? also, when finding the volume of a cylinder, is the formula *Xr(squared)Xthe height or is it different? i have a test tomorrow, so... Link to comment Share on other sites More sharing options...
MathGuy2 Posted September 20, 2002 Share Posted September 20, 2002 [quote]If x+y=7 and z=3x+8, what is the value of z?[/quote] If x+y=7, then x=7-y (subtract y from both sides). Substitute this value for x in the second equation, giving z=3(7-y)+8. Distribute 3 over 7-y, giving z=3*7-3*y+8. Simplify: z=29-3y. There is a theorem somewhere that says that if you want an exact numerical answer, and your equations have [i]n[/i] variables, then you need at least [i]n[/i] equations. The best you can do otherwise is get the answer in terms of another variable. [quote]also, when finding the volume of a cylinder, is the formula *Xr(squared)Xthe height or is it different? i have a test tomorrow, so...[/quote] The formula is (pi)r^2*h, pi times square of radius times height. This comes because the base for a cylinder is a circle, with area (pi)r^2, and that circle is repeated vertically [i]h[/i] times. -HS Freshman in Trig About your history and science questions, try some online encyclopedias. Two questions of my own: what is the plural of "virus", "viruses" or "viri"? And what is the origin of the word "subtend"? Link to comment Share on other sites More sharing options...
Mnemolth Posted September 20, 2002 Author Share Posted September 20, 2002 [QUOTE][i]Originally posted by User Name [/i] [B][SIZE=4]Jeeze, you really do LOVE to show off, don't you? Righty then, history question - What were the major factors contributing to WW2 ? [/SIZE] [/B][/QUOTE] Maybe you should actually go through the thread and actually read some of the posts before commenting. You can begin with the starting post....sheesh... :rolleyes: EDIT: Hmm....and while I'm at it, can I just say the idea is about [i]helping[/i]. So if you know the answer please don't ask questions [i]just[/i] to show up people who are trying to help. And likewise, if you are going to give out advise, be nice about it. The point is not to impress, but to assist. Link to comment Share on other sites More sharing options...
Guest gojay Posted September 20, 2002 Share Posted September 20, 2002 [QUOTE][i]Originally posted by MathGuy2 [/i] [B]If x+y=7, then x=7-y (subtract y from both sides). Substitute this value for x in the second equation, giving z=3(7-y)+8. Distribute 3 over 7-y, giving z=3*7-3*y+8. Simplify: z=29-3y. There is a theorem somewhere that says that if you want an exact numerical answer, and your equations have [i]n[/i] variables, then you need at least [i]n[/i] equations. The best you can do otherwise is get the answer in terms of another variable. The formula is (pi)r^2*h, pi times square of radius times height. This comes because the base for a cylinder is a circle, with area (pi)r^2, and that circle is repeated vertically [i]h[/i] times. -HS Freshman in Trig About your history and science questions, try some online encyclopedias. Two questions of my own: what is the plural of "virus", "viruses" or "viri"? And what is the origin of the word "subtend"? [/B][/QUOTE] :cool: [size=1][color=blue]Wow, thanks alot.:)[/size][/color] Link to comment Share on other sites More sharing options...
Senor Ding Dong Posted September 22, 2002 Share Posted September 22, 2002 i know this is not math, but i need help with something non related. see, for christmas, i plan on getting a ps2. but my dad, the guy with the money, says he won't spend money on something that in a few years will be replaced. i have an outdated ps1, and i REALLY, REALLY want to own kingdom hearts.so how can i convince him? Link to comment Share on other sites More sharing options...
Mnemolth Posted September 22, 2002 Author Share Posted September 22, 2002 [QUOTE][i]Originally posted by clowmet [/i] [B]i know this is not math, but i need help with something non related. see, for christmas, i plan on getting a ps2. but my dad, the guy with the money, says he won't spend money on something that in a few years will be replaced. i have an outdated ps1, and i REALLY, REALLY want to own kingdom hearts.so how can i convince him? [/B][/QUOTE] For a variety of reasons its really hard to help someone out with something like this. I would say something silly like show your dad how much you want PS2 by volunteering to do things about the house for it. Or if you are given pocket money bargain with him that for every dollar you save for PS2 he will give you 4 or something like that. I really have no idea. [b]And its quite ok to ask questions that are NOT math related. This thread is not just for help with maths, its for ALL kinds of homework. Actually, I would welcome other material, maybe in science or law, etc[/b] Though we can probably help each other better if the questions are of a kind that HAS answers. ;) Link to comment Share on other sites More sharing options...
Defcon5 Posted September 23, 2002 Share Posted September 23, 2002 Math here, How do you convert kg-g using some weird formula (We can't move the decimal point for some reason.) Hopefully one of you can explain it better than my science teacher Link to comment Share on other sites More sharing options...
Mnemolth Posted September 23, 2002 Author Share Posted September 23, 2002 Huh?? I'm not sure what you mean. It seems like you're talking about converting kg (kilograms) to g (grams). But that's a litle obvious? Anyways, I'll just assume that's what you're asking, k? ;) 1 kg = 1000 g So to covert kg to g, just move the decimal place 3 places to the RIGHT. Eg 1.23kg = 1230g (remember to add the 0 to make up at last FOUR digits) 1.2345678kg = 1234.5678g 0.1 kg = 100g (note: you don't put 0100g, cos the first '0' is NOT used) 0.1kg is the SAME as 0.100kg To convert g to kg, just do the opposite. Move the decimal place 3 places to the LEFT. So 234g = 0.234kg 10g = 0.01kg (this is the same as 0.010kg) 1234 = 1.234kg and so on.... Link to comment Share on other sites More sharing options...
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